Reetika Hooda Advances to Quarterfinal of Women's Wrestling Freestyle 76 Kg Event at Paris Olympics 2024, Defeats Hungary's Nagy Bernadett on Technical Superiority
Reetika, who is the first Indian female wrestler to qualify in this weight category in the Olympics, will face Aiperi Medet of Kyrgyzstan who is the top seed of the category in the quarterfinal.
India's last candidate in the Paris Olympics 2024, Reetika Hooda, stays alive as she beats Hungary'sย Nagy Bernadett with technical superiority in the round of 16 bout to enter the quarterfinal. Reetika took the lead early with four points but lost two going in the break. She returned strong with good counterattacks and finished the game 12-2 in her favour. Reetika will faceย Aiperi Medet of Kyrgyzstan who is the top seed of the category in the quarterfinal.ย Vinesh Phogat Disqualification: CAS to Give Decision On Star Wrestler's Appeal On August 10 Evening.
Reetika Hooda Advances to QuarterFinal of Women's Wrestling Freestyle 76 Kg
๐ฎ๐ณ๐ ๐ง๐ผ๐ฝ ๐ฝ๐ฒ๐ฟ๐ณ๐ผ๐ฟ๐บ๐ฎ๐ป๐ฐ๐ฒ ๐ณ๐ฟ๐ผ๐บ ๐ฅ๐ฒ๐ฒ๐๐ถ๐ธ๐ฎ! A great effort from Reetika Hooda to defeat 8th seed, Bernadett Nagy, in the round of 16 in the women's freestyle 76kg category.
๐คผโโ Final Score: Reetika 12 - 2 Bernadett
โฐ She will next take on Aiperi Medet Kyzyโฆ pic.twitter.com/rDQdzNqnDL
โ India at Paris 2024 Olympics (@sportwalkmedia) August 10, 2024
(The above story first appeared on LatestLY on Aug 10, 2024 03:21 PM IST. For more news and updates on politics, world, sports, entertainment and lifestyle, log on to our website latestly.com).
