Paris, Aug 10 (PTI) Indian wrestler Reetika Hooda lost a close quarter-final bout against Aiperi Medet Kyzy of Kyrgyzstan in the women's 76 kg freestyle category at the Paris Olympics here on Saturday.

The wrestlers were locked 1-1 after six minutes of top-quality defensive wrestling but the Kyrgyz won having logged home the last equalising point as per rules.

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Both wrestlers played a defensive game and the solitary point each was scored through passivity across the two periods.

Reetika will now wait for Kyzy to enter the final which will give her a shot at competing in the repechage round.

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If she doesn't then India's Paris Games campaign will end with six medals and without a gold.

Earlier, Reetika displayed power and skill in equal measure while outclassing Bernadett Nagy of Hungary 12-2 in the pre-quarterfinals. 7/21/2024

(The above story is verified and authored by Press Trust of India (PTI) staff. PTI, India’s premier news agency, employs more than 400 journalists and 500 stringers to cover almost every district and small town in India.. The views appearing in the above post do not reflect the opinions of LatestLY)