Dubai, Oct 18 (PTI) Mumbai Indians skipper Rohit Sharma won the toss and opted to bat against Kings XI Punjab in an IPL match here on Sunday.

Both the teams have retained their playing XI from last game.

Also Read | Kane Williamson Praised Online for His Quick Knock Despite Batting With Hamstring Injury During SRH vs KKR IPL 2020 Match.

While defending champions Mumbai (12) are currently at the second spot in IPL standings, KXIP are languishing at the bottom with just four points.

The Teams:

Also Read | Mumbai Indians vs Kings XI Punjab, IPL 2020 Toss Report and Playing XI Update: Mumbai Indians Wins Toss, Elects to Bat.

Mumbai Indians: Rohit Sharma (c), Quinton de Kock (w), Suryakumar Yadav, Ishan Kishan, Hardik Pandya, Kieron Pollard, Krunal Pandya, Nathan Coulter-Nile, Rahul Chahar, Trent Boult, Jasprit Bumrah.

Kings XI Punjab: KL Rahul (w/c), Mayank Agarwal, Chris Gayle, Nicholas Pooran, Glenn Maxwell, Deepak Hooda, Chris Jordan, Murugan Ashwin, Mohammed Shami, Ravi Bishnoi, Arshdeep Singh.

(The above story is verified and authored by Press Trust of India (PTI) staff. PTI, India’s premier news agency, employs more than 400 journalists and 500 stringers to cover almost every district and small town in India.. The views appearing in the above post do not reflect the opinions of LatestLY)