MI vs SRH Toss Report and Playing XI, IPL 2022: Both Teams Make Changes As Rohit Sharma Opts To Bowl
Rohit Sharma has decided that Mumbai Indians will bowl first against Sunrisers Hyderabad in match 65 of IPL 2022. Both teams make two changes as they aim to win the game.
Mumbai Indians have won the toss and skipper Rohit Sharma has been decided that the team will be fielding first in IPL 2022 clash against Sunrisers Hyderabad. Mayank Markande and Sanjay Yadav come in for MI for their first appearances this season.
Sunrisers Hyderabad (Playing XI): Abhishek Sharma, Kane Williamson(c), Rahul Tripathi, Aiden Markram, Nicholas Pooran(w), Priyam Garg, Washington Sundar, Bhuvneshwar Kumar, Fazalhaq Farooqi, Umran Malik, T Natarajan.
Mumbai Indians (Playing XI): Ishan Kishan(w), Rohit Sharma(c), Daniel Sams, Tilak Varma, Ramandeep Singh, Tristan Stubbs, Tim David, Sanjay Yadav, Jasprit Bumrah, Riley Meredith, Mayank Markande.
Match 65. Mumbai Indians won the toss and elected to field. https://t.co/P6lAavLzcL #MIvSRH #TATAIPL #IPL2022
— IndianPremierLeague (@IPL) May 17, 2022
(The above story first appeared on LatestLY on May 17, 2022 07:07 PM IST. For more news and updates on politics, world, sports, entertainment and lifestyle, log on to our website latestly.com).
